typical molecular speeds (vrms) are large, even at low temperatures. what is vrms (in m/s) for helium atoms at 4.85 k, less than one degree above helium's liquefaction temperature? m/s



Answer :

V rms (in m/s) for helium atoms at 4.85 k, less than one degree above helium's liquefaction temperature is calculated as 173.84 m/s.

What is molecular speeds?

Speed of the molecules in a gas is directly proportional to the temperature and inversely proportional to molar mass of the gas. We can also say that, as the temperature of a sample of gas is increased, molecules speed up then the root mean square molecular speed also increases.

As we know that, V rms = √3 KT/M he

Given T= 4.85 K, K= 1.38 *10^-23 and M he is 6.644 *10^-27.

=√ 3 * 1.38 *10^-23 * 4.85 / 6.644 *10^-27

V rms for helium atoms = 173.84 m/s

To know more about molecular speeds, refer

https://brainly.com/question/28069275

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