a 550 kg satellite is in a circular orbit at an altitude of 400 km above the earth's surface. because of air friction, the satellite eventually falls to the earth's surface, where it hits the ground with a speed of 2.20 km/s. how much energy was transformed into internal energy by means of air friction?



Answer :

The energy was transformed into internal energy by means of air friction is equal to 1.2789 × 10⁹J.

What is the law of conservation of energy?

According to the law of conservation of energy, energy can be transformed from one to another but it is not possible to create or destroy it. Energy happens in nature in various forms such as heat, chemical energy, electricity, nuclear energy, and so on.

The sum of the potential energy and kinetic energy before and after are equal.

PE₁ + KE₁ = PE₂ + KE₂ + Qₙ

where Qₙ is the heat energy.

The kinetic energy at the initial stage is zero.

PE₁ = PE₂ + KE₂ + Qₙ

[tex]\displaystyle -(\fracGMm}{R+h} ) =-(\frac{GMm}{R} ) +\frac{1}{2}mv^2 +Q_f[/tex]

[tex]\displaystyle Q_f = (\frac{GMm}{R} ) - (\frac{GMm}{R+h} ) -\frac{1}{2}mv^2[/tex]

[tex]\displaystyle Q_f = {6.67\times 10^{-11}\times 5.98\times 10^{24}\times 550}[(\frac{1}{6.371 \times 10^6} ) - (\frac{1}{6.371 \times 10^6 +400\times 10^3} )] -\frac{1}{2}(550)(2200)^2[/tex]

Heat energy = 1.2789 × 10⁹J

Learn more about the law of conservation of energy, here:

brainly.com/question/12050604

#SPJ1

Other Questions