F=kq1q2r2→k(−q1)(−q2)r2=(−1)2kq1q2r2=F
Electron are positive and the charge can be considered as q.
Proton are negative and the charge can be considered as -Q.
If protons were negatively charged, and electrons were positively charged, this would be equivalent to flipping the signs of all charges∗. Given that, it is quite simple to check that Coulomb's Law obeys charge symmetry, by applying the substitutions q1→−q1 and q2→−q2.
F=kq1q2r2→k(−q1)(−q2)r2=(−1)2kq1q2r2=F
Therefore, there would be no difference if we switched the sign convention of the charges
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