Answer :
The magnitude of the force acting on q will be 0.16 t/s times the magnitude of the charge q, and it will be in the opposite direction of the magnetic field.
The force on a charged particle in a magnetic field is given by the equation:
F = qv × B
where q is the charge of the particle, v is the velocity of the particle and B is the magnitude of the magnetic field.
When the magnitude of the magnetic field is decreased at a rate of -0.16 t/s, the force on the particle will be in the opposite direction of the decreasing magnetic field. This is because the magnitude of the magnetic field will be decreasing over time, so the force on the particle will be in the opposite direction of the decreasing magnetic field.
The magnitude of the force acting on the particle will be equal to the product of the charge of the particle and the velocity of the particle multiplied by the rate of change of the magnetic field. That is, the magnitude of the force will be:
F = qv × (-0.16 t/s)
The direction of the force will be in the opposite direction of the decreasing magnetic field.
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