Answer :
The pressure exerted on the mirror by the light emitted from the 200-w incandescent light bulb is negligible. This is because the pressure exerted by light is proportional to the intensity of the light, and the intensity of the light drops off as the square of the distance. At a distance of 5.0 m, the intensity of the light is extremely low, and thus the pressure is practically zero.
Step 1: Calculate the intensity of light:
We know that the power of the light bulb is 200 W, so the intensity of light is given by:
I = P/4πd2
Where P is the power of the light and d is the distance from the light to the mirror.
In this case, we have:
I = 200 W / 4π(5.0 m)2
I = 0.0025 W/m2
Step 2: Calculate the pressure exerted by the light on the mirror:
We know that the pressure exerted by the light on the mirror is given by:
P = I/c
Where I is the intensity of the light and c is the speed of light.
In this case, we have:
P = 0.0025 W/m2/3.00 x 108 m/s
P = 8.3 x 10-10 N/m2
Therefore, the pressure exerted by the light emitted from the 200-w incandescent light bulb on a mirror at a distance of 5.0 m is 8.3 x 10-10 N/m2.
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