if pressure increases by 1.000 atm for every 10.00 m of depth, at what depth was the diver working? assume the temperature remains constant.

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07-12-2022
Physics

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if pressure increases by 1.000 atm for every 10.00 m of depth, at what depth was the diver working? assume the temperature remains constant.

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jaiswaljyoti jaiswaljyoti · Answer 1 · 2022-12-17T21:56:37-05:00

The diver was working at a depth of 100 m. This can be determined by solving the following equation:

1.000 atm × 10.00 m = X atm × 100 m

X = 10 atm

This means that the pressure increased by 10 atm for every 100 m of depth, which means the diver was working at a depth of 100 m.

Since the temperature remained constant, the pressure increase was solely due to the change in depth.

The pressure increases by 1.000 atm for every 10.00 m of depth. This is known as the hydrostatic pressure equation, which states that pressure (P) is equal to the density of the fluid (rho) multiplied by the acceleration of gravity (g) multiplied by the depth (h):

P = rho * g * h

In this case, we can rearrange the equation to solve for h, the depth at which the diver was working:

h = P / (rho * g)

Since we know that the pressure increases by 1.000 atm for every 10.00 m of depth, we can assume that the pressure at the depth at which the diver was working is P. Therefore, we can substitute P for the pressure in the equation:

h = P / (rho * g)

Since the temperature remains constant, we can assume that the density of the fluid (rho) is also constant. Therefore, we can substitute the value of rho into the equation:

h = P / (rho * g)

Finally, we can substitute the value of acceleration of gravity (g) into the equation:

h = P

To know more about acceleration click here

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