If the lens is immersed in water, its focal length will be 53.6 cm.
A converging lens is that causes parallel rays (as of light) to come to a focus. By noticing that parallel light rays entering and leaving the lens would undergo fewer variations in index of refraction if it were surrounded by water, we may provide a conceptual response to this question. They would thus bend less and concentrate further away from the lens.
The focal length of a thin lens in air is the separation between its major foci, also known as focal points, and its center. The focal length is the distance at which a beam of collimated light will be concentrated to a single spot for a converging lens (for instance, a convex lens).
We can answer this question as follows;
1/f = (1.52−1)( 1/R1 - 1/R2) = 1/50
But lens surrounded by water n = 1.3333 we have
1/f = ((1.52/1.3333)−1)( 1/R1 - 1/R2)
Solving for f we get f=53.6cm
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