Answer :
The speed of a point on earth's surface located at 4/5 of the length of the arc between the equator and the pol is 429 m/s.
How to calculate speed of point on earth's surface:
- The earth's radius is 6.37 × 10⁶ m, it rotates once every 24 hours.
- A point located 1/4 of the length of the arc between the equator and the pole, ([tex]\frac{4}{5}[/tex]) × 90° = 72°
- Since the arc angle of the line joining the equator and the pole is 90°, then the angle between the line joining the center and the given point, and the line joining center and the pole is,
Φ = 90° - 72° = 18°
Sin Φ = (radius of the point ) / (radius of the earth)
Sin 18 = radius of the point / (6.37 × 10⁶)
- Then we should look for the radius point by;
Sin (18) = 0.3090
r = (6.37 × 10⁶) × 0,3090= 1,9683 × 10⁶ m
- Speed of the point on the globe is v = 2πr / (24 hours), then
- 2πr = 2π × 1,9683 × 10⁶ =
- 37095 × 10⁷ m
- Then we can look for the speed of the point by:
v = 37095 × 10⁷/24
v = 1.545 × 10⁶ m/h
= 1545 m/h
= 429 m/s
- Then the result of speed of point on earth's surface is 429 m/s.
Learn more about speed of point on earth's surface here: brainly.com/question/1542471
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