evaluate the definite integral using the fundamental theorem of calculus, part 2, which states that if f is continuous over the interval [a, b] and f(x) is any antiderivative of f(x), then b a f(x) dx



Answer :

The second fundamental theorem of calculus states that if f is continuous on [a,b] and F is an antiderivative of f on the same interval, then:

             [tex]\int\limits^b_a[/tex]f(x) dx = F(b) - F(a)

The second fundamental theorem of calculus states that if f is continuous on [a,b] and F is an antiderivative of f on the same interval, then:

             [tex]\int\limits^b_a[/tex]f(x) dx = F(b) - F(a)

It uses the mean value theorem of integration and the limit of an infinite Riemann summation. But I tried coming up with a proof and it was barely two lines. Here it goes:

Since F is an antiderivative of f, we have dFdx=f(x). Multiplying both sides by dx, we obtain dF=f(x)dx. Now, dF is just the small change in F and f(x)dx represents the infinitesimal area bounded by the curve and the x axis. So integrating both sides, we arrive at the required result.

To learn more about fundamental theorem:

https://brainly.com/question/29015928

#SPJ4