Answer :
The probability of obtaining between 9 and 14 heads is .0.0408
Probability:
in statistics, probability refers the possibility of the outcome of any random event.
Given,
A coin is weighted so that the probability of obtaining a head in a single toss is 0.25.
Here we need to find the probability of obtaining between 9 and 14 heads if the coin is tossed 45 times.
While we looking into the given question,
Probability of obtaining a head in a single toss = 0.25
Number of toss = 45
Here we need to find the probability of getting head between 9 and 14, is calculated as,
=> mean = 45 x 0.25 = 11.25
=> standard deviation = √11.25 x(1 - 0.25) = 2.9
Here the probability is written as,
=> P(9 < x < 14) = P(8.5 < x < 14.5)
Then the z score, is
=> z = (8.5 - 11.25)/2.9 = -0.9483
=> z = (14.5 - 11.25)/2.9 = 1.1207
So, the given probability is rewritten as,
=> P(9 < x < 14) = P(z < 1.1207) - P(z < 0.9483)
When we apply the value of z score on it then we get,
= > P(z < -0.9483) = 0.17149
=> P(z > 1.1207) = 0.13121
=> P(9 < x < 14) = 0.13121 - 0.17149
=> 0.0403
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