Answer :
The first four terms of the given sequence A(n)=4n^3+2 is 6, 34, 110, 258.
In the given question, the nth term of a sequence is given.
We have to write the first four terms of the sequence and we also have to express the terms in simplified form when applicable.
The given sequence is:
A(n)=4n^3+2
We find the four terms of the given sequence by putting n=1,2,3,4 in the given sequence.
Now putting n=1 in the given sequence
A(1)=4(1)^3+2
A(1)=4*1+2
A(1)=4+2
A(1)=6
Now putting n=2 in the given sequence
A(2)=4(2)^3+2
A(2)=4*8+2
A(2)=32+2
A(2)=34
Now putting n=1 in the given sequence
A(3)=4(3)^3+2
A(3)=4*27+2
A(3)=108+2
A(3)=110
Now putting n=1 in the given sequence
A(4)=4(4)^3+2
A(4)=4*64+2
A(4)=256+2
A(4)=258
Now the first four terms of the given sequence is 6, 34, 110, 258.
To learn more about sequence link is here
brainly.com/question/21961097
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The right question is:
The nth term of a sequence is given. Write the first four terms of the sequence. Express the terms in simplified form when applicable.
A(n)=4n^3+2
