A researcher is interested in whether using your finger to follow the words you are reading changes reading speed. He has students complete a reading speed test, first without using their fingers to follow the words and then again while using their fingers to follow the words. The researcher randomly selects a sample of 56 students who, at the beginning of the study, scored an average of 256 words per minute on the reading speed test. In the trial where they used their fingers while they read, the students scored an average of 6 words per minute higher. The standard deviation of the difference scores was 29. Since the sample size is larger than 30, the researcher can assume that the sampling distribution of MD is normal. He uses a repeated-measures t test to test that the mean difference is zero, and he describes the results as follows: In the trial where they used their fingers while they read, the reading speed among students is not significantly different than when they do not use their fingers while they read, t(55) = 1.55, p = 0.127. If the researcher had used a repeated-measures ANOVA to test that the mean reading speed is the same before and after using their fingers while they read, he would describe the results as follows (fill in all missing values): In the trial where they used their fingers while they read, the reading speed among students is different than when they do not use their fingers while they read, F()=, p = 0.127.



Answer :

The confidence interval for the given ANOVA test to calculate the average typing speed be, (144.83 , 155.17) and the margin of error of the poll be, ±5.17

On Subtracting 1 from your sample size, we get

150 – 1 = 149.

On Subtracting confidence level from 1, and then divide by two.

(1 – .95) / 2 = 0.025

Now, df = 149 and α = 0.025

from the table at df = 149 we got 2.262.

Divide your sample standard deviation by the square root of your sample size.

28 / √(150) = 2.28

Now, 2.262 × 2.28 = 5.17

So, the confidence interval be,

(150 - 5.17 , 150 + 5.17) = (144.83 , 155.17)

Hence, the confidence interval for the given ANOVA test to calculate the average typing speed be, (144.83 , 155.17) and the margin of error of the poll be, ±5.17

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