Option (B) is the correct one.
Both of those probabilities decrease.
Given, the number of tosses of a fair coin goes up from 10, to 100, to 1,000 and to 10,000.
we have to find the effect on the probability of getting exactly 50% heads.
In 10 tosses,
we have to get heads 5 times,
P(X = 5) = (1/2)^5(1/2)^5
P(X = 5) = (1/2)^10
In 100 tosses,
we have to get heads 50 times,
P(X = 50) = (1/2)^50(1/2)^50
P(X = 50) = (1/2)^100
and so on.
It is clear that the probability of getting 50% heads decreases.
Also, Probability of getting heads between 40% and 60% decreases.
Hence, both of those probabilities decrease.
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