Answer :
If the dog has a z-score of -1.09, his weight is 48.46kg but if the dog has a z-score of 1.09, his weight is 61.54kg according to given standard deviation.
What is standard deviation?
Standard Deviation is a measure that shows what quantity variation (such as unfold, dispersion, spread,) from the mean exists. the quality deviation indicates a “typical” deviation from the mean. it's a well-liked live of variability as a result of it returns to the first units of live of the info set.
Main body:
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = x- υ/σ
Given that μ = 55, σ = 6;
For x = 49:
z = 49 - 55/6
z = -1
If the dog has a z-score of -1.09, his weight is:
-1.09 = x -55/6
x - 55 = -6.54
x = 48.46
If the dog has a z-score of 1.09, his weight is:
1.09 = x - 55/6
x -55 = 6.54
x = 61.54
Hence ,If the dog has a z-score of -1.09, his weight is 48.46kg but if the dog has a z-score of 1.09, his weight is 61.54kg
To know more about standard deviation , visit:
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