The probability that the sum of the faces is 7 = 15/216
The value of m = 15 and the value of n = 216
In this question, we have been given three regular dice are rolled simultaneously.
We need to find the probability that the sum of the faces is 7.
When three dice are rolled simultaneously, the total number of outcomes
n(S) = 6 * 6 * 6
n(S) = 216
Let event A: sum of the faces is 7
A = {(1, 2, 4), (1, 4, 2), (4, 1, 2), (4, 2, 1), (2, 1, 4), (2, 4, 1), (1, 3, 3), (3, 3, 1), (3, 1, 3), (2, 2, 3), (2, 3, 2), (3, 2, 2), (1, 5, 1), (5, 1, 1), (1, 1, 5)}
n(A) = 15
So, the probability that the sum of the faces is 7 = 15/216
Hence, if the probability that the sum of the faces is 7 can be represented by m/n in simplest form then m = 15 and n = 216
Learn more about the probability here:
https://brainly.com/question/11234923
#SPJ4