point is 9 units from the center of a circle of radius 15. how many different chords of the circle contain and have integer lengths?



Answer :

Total number of different chords of the circle passing through point P with integer lengths is equal to 7.

As given in the question,

Radius of the circle = 15units

Longest chord of the circle 'diameter' = 2 × 15

                                                               = 30units

Point 'P' is 9 units away from the circle.

Consider shortest distance( perpendicular) of point P for shortest chord.

Half length of the chord , shortest distance and radius form right triangle.

(1/2) length of the chord = √15² - 9²

                                        = √225 - 81

                                        = 12units

Length of the chord = 2(12)

                                 = 24 units

Different Chords with integer length = 24, 25, 26, 27, 28 , 29 , 30

Total number of different chords = 7

total number of chords = 6 original + 6 mirror image + 1 longest chord

                                       = 13

Therefore, total chords with different integer length passing through the point P of the circle is 7.

The complete question is :

A point P is at the 9 unit distance from the center of a circle of radius 15 unit. How many total number of different chord of the circle passing through the point P and have the integer lengths?

Learn more about chords here

brainly.com/question/21686011

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