Answer :
Th number of possible ways for
a) each player gets exactly 13 cards = 52! / (13! 13! 13! 13!)
b) each player gets seven cards and the rest of the cards remain in the deck = 52! / (7! 7! 7! 7! 24!)
In this question, we have been given that there are four players. the select cards from the standard deck of 52 cards.
We need to find the number of possible ways for given situations.
(a) each player gets exactly 13 cards.
Using combination, we get an expression,
^{52}C_13 * ^{39}C_13 * ^{26}C_13 * ^{13}C_13
= 52! / (13! 13! 13! 13!)
= 53644737765488792839237440000
(b) each player gets seven cards and the rest of the cards remain in the deck
Using combination, we get an expression,
^{52}C_7 * ^{45}C_7 * ^{38}C_7 * ^{31}C_7 * ^{24}C_24
= 52! / (7! 7! 7! 7! 24!)
Therefore, a) each player gets exactly 13 cards = 52! / (13! 13! 13! 13!)
b) each player gets seven cards and the rest of the cards remain in the deck = 52! / (7! 7! 7! 7! 24!)
Learn more about combination here:
https://brainly.com/question/28720645
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