Answer :
The foot be moving away from the wall when the top is 10 feet above the ground is 2.4077
How to solve word problems?
It's actually fairly easy to solve word problems using a tried-and-true step-by-step approach.
- Aloud to yourself, read the issue.
- Make a Drawing.
- Ask yourself, "What am I looking for?"
- List the items that have been provided.
- Locate the key phrases, then Solve.
- Verify your work.
The ladder against the wall is a right triangle:
x² + y² = 15²
Top slips down => dy/dt = -2 ft/s. When y = 10 ft. dx/dt = ?
1) Take the derivative with respect to time:
2x (dx/dt) + 2y (dy/dt) = 0
2) Substitute y = 10, x =sqrt(69) z =15
2(sqrt(69)) (dx/dt) + 2(10) (-2) = 0
dx/dt = 40/2(sqrt(69))
dx/dt = 20/(sqrt(69))
= 20/8.30
=2.4077
Hence, the foot be moving away from the wall when the top is 10 feet above the ground is 2.4077.
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https://brainly.com/question/13818690
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