Answer :
The true statements are work done by the gas is positive and the work done on the gas is negative.
We know that the work done by the gas is given by
Work done = ∫Pdv
If we assume P to be a constant, then
W₁ = P∆V
It is given that the gas expands, therefore expansion of gas results in a positive value of ∆V. Therefore, the work done will also be positive.
W₁ = positive
Then it should also be noted that,
Work done by the gas W₁ = - (Work done on the gas W₂)
W₁ = -W₂
Then,
W₂ = -W₁
Then W₂ is negative.
Therefore, then it could be concluded that the
Work done by the gas is positive and
Work done on the gas is negative.
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