explain why the following reaction yields the hoffman product (least substituted alkene) and no zaitsev product at all, even though the base is not sterically hindered.

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25-11-2022
Chemistry

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explain why the following reaction yields the hoffman product (least substituted alkene) and no zaitsev product at all, even though the base is not sterically hindered.

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Neetoo Neetoo · Answer 1 · 2022-12-07T04:48:56-05:00

The following reaction yields the Hoffman product and no Zaitsev product at all, even though the base is not sterically hindered because it proceeds through the E2 mechanism.

The reaction is under through E2 mechanism. In the E2 mechanism, the base abstracts the proton that is opposite to the leaving group. Bromine is the leaving group in the above-mentioned molecule, having two neighboring hydrogen atoms. The hydrogen atom opposite the bromine atom can take part in the E2 reaction. and the hydrogen having the same side as bromine cannot take part in the reaction. So the reaction yields the Hoffman product and no Zaitsev product at all.

The complete question is attached.

You can also learn about E2 mechanism from the following question:

https://brainly.com/question/2049168

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