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the length of a rectangle is increasing at a rate of 3 cm/s and its width is increasing at a rate of 5 cm/s. when the length is 15 cm and the width is 13 cm, how fast is the area of the rectangle increasing (in cm2/s)?



Answer :

abiolataiwo2015

If the length of a rectangle is increasing at a rate of 3 cm/s and its width is increasing at a rate of 5 cm/s. The area of the rectangle increasing is:  114 cm2/sec.

How to find the area of the rectangular?

Using product rule formula

(dA / dt) = L× (dW / dt) + W × (dL / dt)

Where:

dA/dt = Rate that the area of the rectangle is increasing

dL/dt = 3 cm/s

L = 15 cm

dW/dt = 5 cm/s

W = 13 cm

Let plug in the formula

(dA / dt) = (15) × (5) + (13) × (3)

(dA / dt) = 75 + 39

(dA / dt)  = 114 cm2/sec

Therefore 114 cm2/sec is the area of the rectangular.

Learn more about area of the rectangular here:https://brainly.com/question/25292087

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