the amount of snowfall falling in a certain mountain range is normally distributed with a mean of 70 inches and a standard deviation of 10 inches. what is the probability that the mean annual snowfall during 25 randomly picked years will exceed 72.8 inches?



Answer :

80.8% of the time, the average yearly snowfall across the 25 years that were randomly chosen will be greater than 72.8 inches.

Describe the term Normal Distribution?

  • When we are aware of the normal distribution of the data, we must utilize that normal distribution to calculate probabilities.
  • That is, in order to determine the necessary area under the normal curve, we must use the mean and indeed the population standard deviation.

As the question stated;

The z score is estimated as;

z = (x - μ)/σ

In which,

Mean μ =  70 inche

standard deviation σ = 10 inches.

n = 25

z = (72.8 - 70)/(10/√25)

z = 2.8/2

z = 1.40

Use z-score table to find the value;

P(x > 72.8 inches) = P(z > 1.40)

P(x > 72.8 inches) = 1 - P(z < 1.40)

P(x > 72.8 inches) = 1 - 0.9192

P(x > 72.8 inches) = 0.0808

Thus, 80.8% of the time, the average yearly snowfall across the 25 years that were randomly chosen will be greater than 72.8 inches.

To know more about the Normal Distribution, here

https://brainly.com/question/4079902

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