what total energy (in kj) is contained in 1.00 moles of photons, all with a wavelength of 0.00000187 m? your answer should have three significant figures and no units.



Answer :

The total energy contained in a given number of photons depends on the energy of each photon. The energy of a photon is directly proportional to its frequency and inversely proportional to its wavelength.

To find the energy of a photon with a given wavelength, you can use the formula E = h * c / lambda, where E is the energy of the photon, h is the Planck constant (6.62607015 x 10^-34 J*s), c is the speed of light (2.99792458 x 10^8 m/s), and lambda is the wavelength of the photon.

In this case, the wavelength of the photon is 0.00000187 m, so the energy of a single photon would be: E = 6.62607015 x 10^-34 J * s * 2.99792458 x 10^8 m/s / 0.00000187 m = 1.97639 x 10^-19 J.

If we have 1.00 moles of photons, each with an energy of 1.97639 x 10^-19 J, the total energy contained in the photons would be the number of photons times the energy of each photon. One mole of any substance contains 6.02214076 x 10^23 particles, so 1.00 moles of photons would contain 6.02214076 x 10^23 photons.

To find the total energy contained in 1.00 moles of photons with a wavelength of 0.00000187 m, we can multiply the number of photons by the energy of each photon: 6.02214076 x 10^23 photons * 1.97639 x 10^-19 J/photon = 1.1933 x 10^5 J.

To convert this to kJ, we can divide by 1000 to get 119.33 kJ. Rounded to three significant figures, the total energy contained in 1.00 moles of photons with a wavelength of 0.00000187 m would be 119 kJ.

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