Answer :

The reaction between 1 mole of oxygen gas and 1 mole of ethanol has oxygen gas (O2) as the limiting reactant.

equilibrium equation

2CO2 + 3H2O > CH3CH2OH + 3O2

Three moles of oxygen (O2) and one mole of CH3CH2OH (from the previous equation) interacted.

Three moles of O2 and one mole of CH3CH2OH reacted from the above balanced equation.

As a result, 1 mole of O2 will react with 0.33 moles of CH3CH2OH (1/3)

From the preceding calculation, we can see that just 0.33 moles of the given 1 mole of CH3CH2OH are required for a complete reaction with 1 mole of O2.

O2 is the limiting reactant as a result.

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The complete question is

CH3CH2OH + 302 → 2002 + 3H20

What would be the limiting reactant in the reaction if 1 mole of

oxygen gas and 1 mole of ethanol (CH3CH2OH) reacted with

each other?