Answer :
The value of the 60th term is -721 in given arithmetic progression or we call as AP
What is arithmetic progression?
The difference between every two successive terms in a sequence is the same; this is known as an arithmetic progression (AP).
It is possible to obtain a formula for the nth term of the AP using this kind of development.
A good example of an arithmetic progression (AP) is the series 2, 6, 10, 14,..., which follows a pattern in which each number is created by adding 4 to the previous term.
The nth term in this series equals 4n-2. You can get the sequence's terms by inserting n=1,2,3,...
Given:
-13, -25, -37, -49,..
a = -13
d = t₂ - t₁
= -25 - (-13)
= -25 + 13
d = -12
tₙ = a +(n-1) d
t₆₀ = -13 + (60-1) (-12)
= -13 + (59) (-12)
= -13 - 708
t₆₀ = -721
Hence, the value of the 60th term is -721 in given arithmetic progression.
complete question is
Find a formula for the
nth term, Tn, of the following arithmetic sequence:−13,−25,−37,−49
,. . . Hence, or otherwise, find the value of the 60th term,
T60
To know more about arithmetic check the below link:
brainly.com/question/28882428
#SPJ4
