Answer :

A net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid is :

H₂C₂O₄  +  2OH⁻  ---->     C₂O₄²⁻   +  2H₂O

The balance molecular equation is given as :

2NaOH (aq)   +   H₂C₂O₄ (aq)   ----->  Na₂C₂O₄ (aq)    +  2H₂O (l)

now, the complete ionic equation is given as :

H₂C₂O₄ +  2Na⁺   +  2OH⁻  ---->   2Na⁺   +  C₂O₄²⁻   +  2H₂O

cancel out the spectators ion the spectators ions are those which are on both side the reactant side and the product side : the net ionic equation is given as :

H₂C₂O₄  +  2OH⁻  ---->     C₂O₄²⁻   +  2H₂O

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