The sample size of the given question is 83 and the t-test value is -0.6578.
Hypotheses:
H0 : Ha: ц < 7.
Sample mean = 6.5
SD = 1.1
n = 83
ц =7
Null hypothesis: ц >= 7
Alternative hypothesis: ц < 7
Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by
t = (mean - ц )/ ц \sqrt{n}
t-test is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value.
t = -0.5 / 0.76
= -0.6578
To learn more about sample size
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