The x value that more contradictory to h0 than 117.2 is the value less than 117.2 and p-value is 0.0465 and the conclusion is we reject h0.
μ = mean = 120
x = 117.2
σ = standard deviation = 10
n = random sample = 36
Lets take the z test,
z = [tex]\frac{x-\mu }{\sigma / \sqrt{n}}[/tex]
= [tex]\frac{117.2 - 120}{10/\sqrt{36}}[/tex]
= [tex]\frac{-2.8}{1.667}[/tex]
= -1.68
From the test, we know test is left tailed and the rejection area is negative. So, the less x than 117.2 the more contradictory to h0.
For p-value use z-score table and we get 0.0465. Because the p-value is less than the appropriate α, which is 0.1, it can be concluded that h0 is rejected.
Thus, the less x value than 117.2 the more contradictory to h0 and we rejected h0 because p-value is lower than appropriate α.
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