an air water vapor mixture at 101.3 kpa has a dry bulb tempearture of 35 and a raltive humidyty of 80%. the mixture is cooled to a dry bulb temperatuire of 20 any condensate formed has a temperature of 22. fin d the heat transfer required

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23-11-2022
Chemistry

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an air water vapor mixture at 101.3 kpa has a dry bulb tempearture of 35 and a raltive humidyty of 80%. the mixture is cooled to a dry bulb temperatuire of 20 any condensate formed has a temperature of 22. fin d the heat transfer required

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AarushiAanand AarushiAanand · Answer 1 · 2022-11-29T07:36:00-05:00

The heat transfer will be 1.53 q during the humidity.

The temperature mostly on the wet-bulb measurement is subtracted from either the temperature mostly on the dry-bulb thermometer, as well as the relative humidity is calculated using a relative humidity chart.

The given data:

raltive humidity = 80%

temperature = 22

It can be determined by the fotmula:

Omega = Pv/Pd-Pv

Pv = pressure of wet bulb

Pd = pressure of dry bulb

Hence, W = 101.3/66=1.53

Therefore, 1.53 q heat will be transferred.

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