Answer :
The correct answers listed below :
A)The percentage of fencers that don't utilize the foil as their primary weapon in A.
B.) X : 0, 1, 2, 3,..., 21
C.) X ~ p(X) ; 10.4
D.) 21 ~ 0.4
E.) 0.0895
F.) Yes. There is a low (less than 1%) chance that all 21 fencers will not use the foil as their primary weapon.
A.) Considering that 60% of fencers reportedly utilize the foil as their primary weapon;
Number of fencers who do not utilize foil as their primary weapon is the random variable (x);
( 100% - 60%) = (1 - 0.6) = 0.4
B.) Possible values for X include:
The sample size is 26;
X : 0, 1, 2,..., 26
The breakdown of X
X ~ B ; X ~ p(X) ; 26 *0.4
=10.4
How many fencers are anticipated to not utilize the foil as their primary weapon in Part (d)?
X * p(x) (x)
=26 * 0.4
= 8.4
= 8 (nearest whole number) (nearest whole number)
Determine the likelihood that eleven will not utilize the foil as their primary weapon in part (e).
P(x = 11)
Using the link between binomial probabilities:
P(x =x) is equal to nCx * px * (1 - p) (n - x)
P(x = 11) = 26C11 * 0.4^11 * 0.6^10
P(x = 11) = 0.0895
Would you be shocked if none of the 21 used foil as their primary weapon based on the numbers?
P(x = 26) = 26C21 * 0.4^26 * 0.6^0
P(x = 26) = < 0.00001 ( about 0) ( approximately 0)
It will therefore be surprising if all 26 do not employ foil as their primary weapon given this extremely low value, which is virtually equal to 0.
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