Answer :
Yes, the given curves are orthogonal.
What is orthogonal trajectory?
In mathematics, an orthogonal trajectory is a curve, which intersects any curve of a given pencil of (planar) curves orthogonally.
Given equation is,
x²+y²=ax
Differentiating,
2x+2yy'=a
y' = (a-2x)/2y = m1
Again,
x²+y²=by
Differentiating,
2x+2yy'=by'
y' = -2x/(2y-b) = m2
For both curves are orthogonal, we have
m1*m2 = -1
(a-2x)/2y*-2x/(2y-b) = -1
-2ax+4x² = -4y²+2yb
4(x²+y²) = 2ax+2yb
Since, ax = (x²+y²)
by = (x²+y²)
Then,
4(x²+y²) = 2(x²+y²) +2(x²+y²)
4(x²+y²) = 4(x²+y²) (true)
Hence, the above response is appropriate.
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