Answer :
X is the PDA initialization symbol, 0 is the initial state, and 2 is the final state. (0, ∧, X, nop, 2) (0, a, X, push(A), 1) (1, b, A, pop, 0) The following PDA language L = {anbmcn | n, m ≥ 0}. X is the PDA initialization symbol, 0 is the initial state, and 3 is the final state.
In this type of input string, an input can have more than one transition state, so it is called non-deterministic PDAA, where q0 is the initial and final state, ɛ is accepted. For each a, X is pushed onto the stack and the PDA remains in control of the A finite state, reading the string, one symbol at a time (input symbol). Step 2: (state q2) Pop a from the stack when b is seen on the tape. Because they have no memory PDA for L = {0 n1n|n ≥ 0}. (0,ε,X). (1,X,ε). (1,X,ε). 0. 1 If we reach a final state with an.(0,ε,X), the PDA accepts w. (1,X,ε). (1,X,ε). 0. 1. 09-5: Push-down automata. M = (K, Σ, Λ, ∆, s, F) PDA accepts w if we end up with an empty stack.
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