The maximum volume of alkane present in the distillate when the reaction is completed is 18.04 mL of alkane.
When the distillation of methylcyclohexanol is done, the product formed after the distillation is
C₇H₁₄O→C₇H₁₂+H₂O
To find out the volume of alkene mixture, we need to use the density formula which is given as
density=mass/volume
Rearrange the formula for volume
volume=mass/density
We have mass of methylcyclohexanol, which is 14.43g and density is 0.80 g/mL. Plug values in the formula
volume=(14.43g×mL/0.80g)
volume=18.0375 mL
volume=18.04 mL
Therefore, the volume of alkane present in the distillate when the reaction of methylcyclohexanol is completed is 18.04 mL.
To know more about density
https://brainly.com/question/12923671
#SPJ4