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20.00 mL of HCI with an unknown concentration is titrated with 0.450 M NaOH. a. Find the molarity based on the data provided. b. Mark an X on the curve showing where the equivalence point is. c. Draw a circle on the curve where HCl is the excess reactant. d. On the graph, sketch a curve showing what the titration would look like if only 10.00 mL of the same HCl sample were used. 14- 12- 10 8- pH 6- 2- 0- 10 20 30 40 Volume of NaOH (m)



Answer :

The molarity will be 0.45 M by using the given data it will found.

A specific chemical species' concentration inside a solution, specifically the quantity of a solute per unit volume of solution, usually measured by its molar concentration. The quantity of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units, would be the most widely used unit denoting molarity throughout chemistry.

Molarity can be determined by the formula:

M = n/v...(i)

Where m = molarity, n = number of moles and v = volume,

The given data:

Volume (V) = 20. ml

Concentration = 0.450 M

Concentration = moles /volume...(ii)

Put the values of given data in equation (ii)

moles (n) = 0.45 × 20 = 9 moles

Now, put the values of number of moles in equation (i).

Molarity = 9/20 = 0.45

The molarity will be 0.45 M

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