Now compare the distance from the first dark fringe above the middle of the screen (where the intensity is nearly zero) to each of the two slits. How do the distances compare? 500 nm 11310 Light Generator The difference in the distances is equal to a quarter of the wavelength of the wave. The distances are the same The difference in the distances is equal to half the wavelength of the wave, The difference in the distances is equal to the wavelength of the wave.

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23-11-2022
Physics

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Now compare the distance from the first dark fringe above the middle of the screen (where the intensity is nearly zero) to each of the two slits. How do the distances compare? 500 nm 11310 Light Generator The difference in the distances is equal to a quarter of the wavelength of the wave. The distances are the same The difference in the distances is equal to half the wavelength of the wave, The difference in the distances is equal to the wavelength of the wave.

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jaspreetsharma jaspreetsharma · Answer 1 · 2022-11-30T03:53:58-05:00

the distance from the first dark fringe above the middle of the screen o each of the two slit is compared by option c difference in the distance is equal to the half the wavelength of the wave

To obtain the first dark fringe, the light from both slits is phase shifted by pi angle. As a result, the path difference between the two slits is the difference in the distance is equal to the half the wavelength of the wave The interferences that cause the dark fringe formation are destructive in nature. The interference fringes are denoted as destructive in the resultant amplitude, and their intensity is equal to zero.

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