Answer :
At the summit, the ring pushes the rider with a force of 801N.
Centripetal force and force equilibrium are ideas needed to address the challenges.
Calculate the rider's velocity by first multiplying the period by the round-up wheel's complete circumference. The centripetal force acting on the rider may then be calculated using the velocity. The normal force may then be calculated using the force equilibrium.
The radius of a circle is, r=[tex]\frac{d}{2}[/tex]
Here,
d is the diameter of the circle
The circumference of a circle is, C= 2πr
The speed is the total distance covered in a given time. The speed is,
v=[tex]\frac{x}{t}[/tex]
here,
x is the distance covered and t is the time taken
The centripetal force acting on a body moving in a circular path is,
[tex]F_{c}[/tex]=[tex]\frac{mv^{2} }{r}[/tex]
Here,
m is the mass of the body.
The weight of a body is, W=mg
g is the acceleration due to gravity.
step: 1
Part A
The radius of the wheel is, r=[tex]\frac{d}{2}[/tex]
Here, d is the diameter of the wheel
d=16.0m
r=16/2
r=8m
The circumference of the wheel is, c=2*(3.14rad)*(8m)
c= 50.3m
The speed of rider is, v=[tex]\frac{C}{T}[/tex]
v=50.3/3.60
v= 14.0m/s
The centripetal force acting on the rider is, [tex]F_{c}[/tex]=[tex]\frac{mv^{2} }{r}[/tex]
[tex]F_{c}[/tex]=55 * 14/8
[tex]F_{c}[/tex]=1.35*10³
The weight of the rider is, W=mg
W=55*9.81
W=5.40*10²N
The force equilibrium at the top of the wheel is,
-F -W = - [tex]F_{c}[/tex]
F is the force that the ring pushes the rider.
Rewrite the equation in terms of the force that the ring pushes on the rider at the top. The force is, F= [tex]F_{c}[/tex]-W
F=(1.35*10³N)-(5.40*10²N)
F=801N
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