Answer :
When a 22-kg child steps off a 3.0-kg stationary skateboard with an acceleration of 0.50 m/s2, with 3.6 m/s² acceleration will the skateboard travel in the opposite drection.
Using Newton's second law of motion -
Fc = mc * ac
where Fc= force the child puts in stepping off
mc= mass of the child
ac= acceleration of the child
so,
Fc = 22kg * 0.50m/s²
Fc= 11.0 N
Then, the force on the skateboard is-
Fs= ms*as
where Fs= force on the skateboard
ms= mass of the skateboard
as= acceleration of the skateboard in the opposite direction
Fc = Fs, as the skateboard is stationary so it will feel the equal force that the child will puts in stepping off.
We need to find the acceleration of the skateboard -
as = Fc / ms
as = 11N / 3kg
as= 3.6 m/s²
since, the force is opposing the child, it would accelerate in the opposite direction.
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