Answer :
The acceleration of the block moving upward is 5.15g.
The two blocks of mass 5 kg and 4.71 kg are connected by a massless rope, that goes over a frictionless, stationary pulley.
The acceleration of the 5 kg block is 34g in downwards direction.
So, if the tension is the rope is T, then we can write,
For the 5 kg block,
5g - T = 34g
For the 4.71 kg block,
T - 4.71g = 4.71a
Where, a is the upward acceleration of the block of mass 4.71 kg,
Solving the above 2 equations,
We get,
5g - 4.71(a-g) = 34g
Solving further,
9.7g - 4.71a = 34g
4.71a = -24.3g
a = -5.15g
So, the upward acceleration of the 4.71kg block is -5.15g.
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