Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks, with a mass of 5.0 kg accelerates downward at 34g.The mass of the other block moving upwards is 4.71 kg



Answer :

The acceleration of the block moving upward is 5.15g.

The two blocks of mass 5 kg and 4.71 kg are connected by a massless rope, that goes over a frictionless, stationary pulley.

The acceleration of the 5 kg block is 34g in downwards direction.

So, if the tension is the rope is T, then we can write,

For the 5 kg block,

5g - T = 34g

For the 4.71 kg block,

T - 4.71g = 4.71a

Where, a is the upward acceleration of the block of mass 4.71 kg,

Solving the above 2 equations,

We get,

5g - 4.71(a-g) = 34g

Solving further,

9.7g - 4.71a = 34g

4.71a = -24.3g

a = -5.15g

So, the upward acceleration of the 4.71kg block is -5.15g.

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