Answer :
The decreasing radial function has Q= 6.556994.
Given-
Radius of the snowball decreases as the function is decreasing.
The rate is -0.1cm per hour , i.e. 0.01m per hour.
Radial distance of the quadrupole is 15cm , i.e. 0.15m.
[tex]Q=k\frac{1}{\sqrt{4\pi \alpha x} } +Ky^2\\\\Q=\left \{ {{K=0} \atop {y\neq 0}} \right.[/tex]
[tex]Q=k\frac{1}{\sqrt{4\pi \alpha x} }[/tex]
The dipole moment of the snowball has shift or rise in the function.
This is rise in dielectric constant.
x=0.15m
α=0.1
k=9
Calculations-
Q=9 (1/√4x3.14x0.15
Q=9/√1.884
=9/1.37258
Q=6.556994
To know about dielectric constant-
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