Answer :
Two rocks, with mass m and 7m, are dropped from a height h. The kinetic energy of rock with mass 7m is 7 times that of the rock with mass m.
When an object is dropped from a certain height, it will experience a free fall motion. Its velocity just before the object hits the ground is:
v = √(2gh)
Hence, it the velocity doesn't depend on the mass of the object. Therefore, in the given case, the velocity of mass m and mass 7m will be the same.
The kinetic energy of an object with m is given by:
Ek = 1/2 . mv²
Since the velocities of the two rocks are the same, the kinetic energy is directly proportional to their masses.
Ek1 : Ek2 = m1 : m2
Ek1 : Ek2 = m : 7m
Ek2 = 7 Ek1
Thus, the kinetic energy of rock with mass 7m is 7 times that of the rock with mass m.
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