Light with wavelength 500 nm falls on a slit of width 10μm at an angle 30∘ to its normal. Find the angular position of the first minima located on both sides of the central Fraunhofer maximum : a) 33∘ and 27∘; b) 25∘ and 35∘; c) 36∘ and 24∘; d) 28∘ and 32∘

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23-11-2022
Physics

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Light with wavelength 500 nm falls on a slit of width 10μm at an angle 30∘ to its normal. Find the angular position of the first minima located on both sides of the central Fraunhofer maximum : a) 33∘ and 27∘; b) 25∘ and 35∘; c) 36∘ and 24∘; d) 28∘ and 32∘

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-11-26T10:35:32-05:00

The angular position of the first minima located on both sides of the central Fraunhofer maximum : a) 33° and 27° is correct.

Normally, light with a wavelength of 5000 A° is incident on a slit with a width of 2.5× 10⁻⁴cm.

The concept of diffraction is the foundation of the presented issue. The equation: yields the angular coordinates of the black fringes n, which are intercalated dark and bright fringes that are symmetric with regard to the center of the screen.

d × sinθ = n × λ

Where, n is the order of pattern minima, and θ is the angular separation.

n = 1 for first minima. In that case, angular separation is,

d × sinθ = λ

To know more about first minima

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