Answer :
The students should take the measurement of only the distance covered block A while falling to reaching to the ground. Thus, option (c) is correct.
According to Newton's Law:
For Block A:
The forces on block A is tension upwards and force downwards.
Tension = T
Force = mₐ × g
Thus, equating the forces =
= mₐ × g = T + mₐ × a
Then, tension =
= T = (mₐ × g) - (mₐ × a)
= T = mₐ (g - a) [ Let this be equation 1]
For block B:
Tension = mₓ × g
= T = mₓ × g [Let this be equation 2]
Equation equation 1 and 2,
= mₓ × g = mₐ (g - a)
= mₓ = mₐ (g - a) / g
= mₓ = mₐ ( g/a - 1) [Let this be equation 3]
Now, let the distance of fall be = d
The time taken for the fall be = t
Then, the acceleration starting from the rest will be (a) =
= d = (v × t )+ (1/2 × a × t²)
Here, v = 0 m/s as the fall starts from rest
= d = (1/2 × a × t²)
= a = 2 × d / t²
Substituting this is equation 3 =
= mₓ = mₐ ( (g × t²/2×d) - 1)
Hence, the distance of the fall that block A used is required to determine the masses of the blocks.
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