Answer :
A nozzle with an area of 0.3 cm² is attached to a garden hose with an area of 1.8 cm². The flow rate through the nozzle is 0.18 l/s and the flow rate through the garden hose is 0.108* 10⁻³m³/s.
We know that the equation of continuity as Q = A*v
From the above equation, the relation between flow rate and area can be written as Q₁A₂ = Q₂A₁
Given that, flow rate of the nozzle Q₁ = 0.18 l/s = 0.18*10⁻³ m³/s
flow rate of the garden hose Q₂ = ?
area of the nozzle A₁ = 0.3 cm² = 0.3*10⁻⁴ m²
area of the garden hose A₂ = 1.8 cm² = 1.8* 10⁻⁴ m²
Substitute the values in the above equation,
0.18* 10⁻⁴* 0.18*10⁻³ = 0.3*10⁻⁴* Q₂
0.18* 0.18* 10⁻³ = 0.3*Q₂
Q₂ = 0.108* 10⁻³m³/s
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