Answer :
The magnitude of the emf E is 0.0047 V, The Direction of the induced current is clockwise.
What is Emf and current?
In electromagnetism and electronics, an electromotive force is an energy transfer to an electric circuit per unit of electric charge, measured in volts. Devices called electrical transducers to provide an emf by converting other forms of energy into electrical energy.
An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
induced emf e = dphi /dt
so we need an expression for phi = BA = Bpi r^2
and since circumference C = 2 pi r,
we can write that as phi = BA = B* pi (C^22/4 pi^2 2)
phi = BC^2/ 4p
Therefore d phi /dt = (BC/2pi ) (dC/dt)
since we know C is a function of t.
after 8 seconds, the circumference is 160 - 9*15 = 25 cm.
= (0.8)(0.25/2*3.14) )(0.15)
Emf= 0.00477 V or 4.77 mV
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induced current I = emf/R (direction is clockwise)
Hence, the magnitude of the emf E is 0.0047 V and the Direction of the induced current is clockwise.
To learn more about the current and EMF the link is given below:
https://brainly.com/question/18883136?
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