Answer:
-7
Step-by-step explanation:
To solve this system of equations, let's solve for x first. We can move 6y to the other side of the first equation by adding it to both sides. Now we know what x equals:
x = 30 + 6y.
Now, we can substitute that equation in for every x in the 2nd equation, then solve for y.
The second equation becomes:
5(30+6y) - 2y = -46
(150 + 30y) - 2y = -46
Simplify.
150 + 28y = -46
Subtract 150 from both sides
28y = -196
Divide by 28 (to get y by itself)
y = -7
Answer:
y = -7
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}x-6y = 30\\5x-2y =-46\end{cases}[/tex]
Multiply the first equation by -5:
[tex]\implies -5(x-6y)=-5(30)[/tex]
[tex]\implies -5x+30y=-150[/tex]
Add this to the second equation to eliminate the term in x:
[tex]\begin{array}{crcrcl}& 5x & - & 2y & = & \:\:-46\\+&(-5x&+&30y&=&-150)\\\cline{2-6}&&&28y&=&-196\\ \cline{2-6}\end{array}[/tex]
Solve the equation for y:
[tex]\implies 28y=-196[/tex]
[tex]\implies \dfrac{28y}{28}=\dfrac{-196}{28}[/tex]
[tex]\implies y=-7[/tex]