Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation.

(9, 12); y=13x−4



Answer :

Answer:

[tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]

Step-by-step explanation:

Equation of line in slope-intercept form: y = mx + b

Here m is the slope and b is the y-intercept.

    y = 13x - 4

     m₁ =  13

Product of slope of the Perpendicular line m * m₁ = -1

                [tex]\sf m = \dfrac{-1}{m_1}\\\\m = \dfrac{-1}{13}[/tex]

Equation of the line:

      [tex]\sf y = \dfrac{-1}{13}x+b[/tex]

The point (9,12) passes through the line. Substitute the coordinates in the above equation and find the value of 'b'.

     [tex]\sf 12 = \dfrac{-1}{13}*9+b\\\\[/tex]

[tex]\sf 12 + \dfrac{9}{13}=b\\\\ \dfrac{156}{13}+ \dfrac{9}{13}=b\\\\\boxed{b= \dfrac{165}{13}}[/tex]

Equation of line:

          [tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]