Answer :
The number of tosses required is 3.
On a fair toss of dice, outcomes are 1, 2, 3, 4, 5, 6.
So, a dice has 6 possible outcomes.
Probability refers to the measurement of the likelihood of certain events that will occur.
Probability = (Number of desired outcomes)/(Total number of outcomes)
Probability of occurrence of 6 in one toss = 1/6
We have to find that after how many trials probability of 6 becomes 1/2
Let,s say the number of trials = n
1/6 + 1/6 +1/6 ……...upto n times = ½
n*(1/6) = 1/2
n=3.
Here, we just sum up the probability of 6 in one toss n number of times to get the answer as 3.
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