Answer :
The angular displacement of the second of a wrist watch is d)9050 radians. So, correct option is d.
We know very well that angular displacement is defines as the point through which any line or body rotates in any specified direction.
In 1 minute number of seconds are =60
In 60 minutes number of seconds are =60×60=3600
In 24 hours number of seconds are =24×60× 60=86400
So, we have total number of seconds as 86400.
Now, we know that second hand clock completes one revolution of the clock in 60 seconds.
It means, Angular displacement in 60 second = 2π radians
Angular displacement in 1 second = 2π/60=π/30 radians
Therefore, angular displacement in 86400seconds =(π/30)×86400=2880π radians,
which is equivalent to =2880×(22/7)=9050.42radians.
Hence, angular displacement is 9050 radians
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(Complete question) is:
over the course of a day (twenty-four hours), what is the angular displacement of the second hand of a wrist watch. Express your answer in radians?
a)1440radians
b)2880 radians
c)6070 radians
d)9050 radians
