Answered

The table ummarize reult from 984 pedetrian death that were caued by automobile accident. Pedetrian intoxicated
Ye. No
Driver Intoxicated - Ye 51. 75
No 239. 619

If one of the pedetrian death i randomly elected, find the probability that the pedetrian wa intoxicated or the driver wa not intoxicated



Answer :

If one of the pedestrian death is randomly elected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated 0.6290.

  • Divide the applicable variety with the aid of using the whole variety. In this case, the applicable variety they may be requesting is "neither pedestrian nor driver."
  • Neither/Total = 619/984 = 0.6290.
  • Rounded to 4 figures that is 0.6290.
  • This, of course, assumes that the published desk is formatted successfully and is correctly legible.

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