Answer :
Angular momentum of a 0.225kg ball rotating on the end of a thin string in a circle of radius 1.50 m at an angular speed of 10.5 rad/s is 5.315 kg-m²/sec
Angular momentum is defined as the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity.
It is expressed as L = I ω for rotating body.
where, L = angular momentum, I = moment of inertia, ω = angular speed
L = ?, I =?, ω = 10.5
Moment of inertia for the string-mass system is I = mr²
I=?, m= 0.225 , r=1.50
I = 0.225(1.50)²
So, I = 0.506 kg-m²
since, L = I ω
substituting the values I= 0.506, ω= 10.5
L = 0.506 × 10.5
Therefore, L= 5.315 kg-m²/sec
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